What is the area of the two-dimensional cross section that is parallel to face ABC ?Enter your answer in the box. ft²A right triangular prism containing dashed lines representing the hidden edges. The prism is resting on a triangular face, which is labeled D E F and contains right angle E. Side E F is labeled twelve feet. The top of the prism is labeled A B C and contains right angle B. Side A B is labeled five feet and side A C, which is the hypotenuse of the right triangular face, is labeled thirteen feet. The height of the prism is side C F labeled seventeen feet.

Answer:The area of the two-dimensional cross section is 30 feet²Step-by-step explanation:* Lets explain what is the right triangular prism- The right triangular prism has five faces- Two right triangular bases (cross sections)- Three rectangular faces- Its volume V = area of its base × its height- Its surface area SA = the sum of the areas of the five faces- The area of the triangular bases = 1/2 × base of Δ × height of Δ* Lets solve the problem- ABCFED is a right triangular prism- Its two parallel bases are ABC and DEF- Its bases are congruent right triangles∴ AB = DE , BC = EF , AC = DF∵ AB = 5 feet∴ DE = 5 feet- The two-dimensional cross section that is parallel to face ABC   is the face DEF∵ Δ DEF is right triangle , where angle E is a right angle∴ DE and EF are the base and the height of Δ DEF∵ DE = 5 feet ⇒ proved∵ EF = 12 feet ⇒ given∴ The area of Δ DEF = 1/2 × 5 × 12 = 30 feet²∵ The two-dimensional cross section that is parallel to face ABC   is the face DEF* The area of the two-dimensional cross section is 30 feet²